X^2+15x+17=0

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Solution for X^2+15x+17=0 equation: 



X^2+15X+17=0

a = 1; b = 15; c = +17;
Δ = b2-4ac
Δ = 152-4·1·17
Δ = 157
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{157}}{2*1}=\frac{-15-\sqrt{157}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{157}}{2*1}=\frac{-15+\sqrt{157}}{2}
$

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